Question

Suppose that a is an angle with seca alpha = - 11/10 and a is not in the third quadrant. Compute the exact value of sina. You do not have to rationalize the denominatorSin a =

Answer 1

Answer:
`\sin\alpha=0.41628`

Step-by-step explanation:

Given that

`sec\text{ }\alpha=-(11)/(10)`

`\alpha=sec^(-1)(-(11)/(10))=155.4^o`

Now

`\sin\alpha=\sin155.4=0.41628`