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An 80.0 g sample of a gas was heated from 25 ∘C to 225 ∘C. During this process, 346 J of work was done by the system and its internal energy increased by 9135 J. What is the specific heat of the gas?

C=J/(g⋅ ∘C)

User Rodius
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1 Answer

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Step-by-step explanation:

The first law of thermodynamics can be written as:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.

We know that ΔU = 9135 J and W = 346 J. We also know that the gas was heated from 25 ∘C to 225 ∘C. Therefore, the change in temperature is:

ΔT = 225 ∘C - 25 ∘C = 200 ∘C

We can use the specific heat formula to solve for the specific heat of the gas:

Q = mcΔT

where m is the mass of the gas and c is the specific heat of the gas.

Solving for c, we get:

c = Q / (mΔT)

Substituting the given values, we get:

c = 346 J / (80.0 g × 200 ∘C) = 0.0216 J/(g⋅ ∘C)

Therefore, the specific heat of the gas is 0.0216 J/(g⋅ ∘C).

User X Slash
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