Problem is down below Please find the answer.

asked Jan 10, 2024 144k views

4 votes

by Habax

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$(2x-1)^(2) = 25 \iff (2x-1)^(2) = 5^(2)\\$

$x > 0 \implies 2x - 1 = 5 \iff 2x = 5 + 1 \iff 2x = 6 \implies \bf x = 3\\$

$(3y-1)^(2) = 36 \iff (3y-1)^(2) = 6^(2)\\$

$y > 0 \implies 3y-1 = 6 \iff 3y = 6 + 1 \iff 3y = 7 \implies \bf y = (7)/(3)\\$

⇒

$(3x - y)/(x+y) \cdot (1)/(7) = (3(3) - (7)/(3) )/(7(3+(7)/(3) )) = (9 - (7)/(3) )/(7((16)/(3))) = ((27-7)/(3) )/(7((16)/(3)))=\\$

$= ((20)/(3) )/((112)/(3)) = (20)/(3) : (112)/(3) = (20)/(3) \cdot (3)/(112) = (20)/(112) = \bf (5)/(28)\\$

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