Answer:
15838.5 ft
Explanation:
You want the distance an airplane travels at an altitude of 7225 feet from point A at an angle of elevation of 15° to point B at an angle of elevation of 33° on the line in the direction toward the observer.
Tangent
The tangent function relates the angle of elevation to the height and horizontal distance like this:
Tan = Opposite / Adjacent
tan(angle of elevation) = height/(horizontal distance)
The difference in horizontal distances is ...
horizontal distance = height/tan(angle of elevation)
AB = 7225/tan(15°) -7225/tan(33°)
AB = 26964.067 -11125.524 ≈ 15838.5
The plane traveled about 15,838.5 feet from point A to point B.
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