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Find the LCM of:

x² - 3x + 2, x² + x + 2​

User Yanigisawa
by
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1 Answer

7 votes

Answer:

The two polynomials cannot be factored using integer coefficients. Therefore, we need to use the quadratic formula to find their roots:

For x² - 3x + 2 = 0:

a = 1, b = -3, c = 2

x = (-(-3) ± √((-3)² - 4(1)(2))) / (2(1)) = (3 ± √1) / 2

x = 1 or x = 2

For x² + x + 2 = 0:

a = 1, b = 1, c = 2

x = (-1 ± √(1² - 4(1)(2))) / (2(1)) = (-1 ± √(-7)) / 2

x = (-1 ± i√7) / 2

Therefore, the LCM of x² - 3x + 2 and x² + x + 2 is:

(x - 1)(x - 2)(x - (-1/2 + i√7/2))(x - (-1/2 - i√7/2))

User Imran Ali
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