Final answer:
To calculate the molarity of the sodium acetate solution, you can use the equation pH = -log[H+]. From the given pH value, you can calculate the pOH and then the concentration of hydroxide ions. Using this information, you can determine the molarity of the sodium acetate solution.
Step-by-step explanation:
In this problem, we are given the pH of a solution of sodium acetate (NaCH3COO) and the acid-dissociation constant (Ka) for acetic acid. We can use this information to calculate the molarity of the sodium acetate solution.
The pH of a solution can be calculated using the equation pH = -log[H+], where [H+] represents the concentration of hydrogen ions. Since the solution is basic with a pH of 9.41, we can assume that [H+] is very small and can be neglected. Therefore, we can use the formula pOH = 14 - pH to calculate the pOH value, which in this case is 14 - 9.41 = 4.59.
The pOH value can be used to calculate the hydroxide ion concentration, [OH-], using the equation pOH = -log[OH-]. By rearranging this equation, we can solve for [OH-] and get a concentration of 10^(-4.59) M.