Question

The length of Trevor’s pool is 5feet more than 3 times it’s width. The deck surrounding the pool is 2 feet in width. The area of the deck is 196 feet squared. What is the width of the pool.

Answer 1

Since we know that the area of the deck is 196 square feet, we can set up an equation to solve for x: 16 x + 36 = 196. Solving for x, we get x = 10.
So, the width of Trevor’s pool is 10 feet.

Answer 2

Let's start by defining some variables to represent the width and length of the pool:

Let w be the width of the pool (in feet).

Let l be the length of the pool (in feet).

We know from the problem statement that the length of the pool is 5 feet more than 3 times its width:

l = 3w + 5

We also know that the deck surrounding the pool is 2 feet wide. This means that the overall width of the pool and the deck combined is:

w_total = w + 2 + 2 = w + 4

Similarly, the overall length of the pool and the deck combined is:

l_total = l + 2 + 2 = l + 4

We are given that the area of the deck is 196 square feet. The area of the deck can be calculated by subtracting the area of the pool from the area of the pool and deck combined:

Area of deck = Area of pool and deck - Area of pool

196 = w_total * l_total - w * l

We can substitute the expressions for w_total and l_total in terms of w and l:

196 = (w + 4) * (l + 4) - w * l

Simplifying this expression gives:

196 = wl + 4w + 4l + 16

We can substitute the expression for l in terms of w:

196 = w(3w + 5) + 4w + 4(3w + 5) + 16

Simplifying this expression gives:

196 = 13w + 36

Solving for w, we get:

w = 14

Therefore, the width of the pool is 14 feet.