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Bob’s school is selling tickets to a concert. On Monday, the school sold 3 student tickets and 1 adult ticket for a total of $38. On Tuesday, the school made $52 by selling 3 student tickets and 2 adult tickets. Find the price of a student ticket and the price of an adult ticket. SHOW YOUR WORK.

User Yrahman
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Answer:

Let's call the price of a student ticket "s" and the price of an adult ticket "a".

From the first day's sales, we know that:

3s + 1a = 38

From the second day's sales, we know that:

3s + 2a = 52

We can use these two equations to solve for "s" and "a".

First, we'll use the first equation to solve for "a":

3s + a = 38

a = 38 - 3s

Next, we'll substitute this expression for "a" into the second equation:

3s + 2(38 - 3s) = 52

Simplifying and solving for "s", we get:

3s + 76 - 6s = 52

-3s = -24

s = 8

So the price of a student ticket is $8.

We can substitute this value back into the first equation to solve for "a":

3(8) + a = 38

24 + a = 38

a = 14

So the price of an adult ticket is $14.

User Damith
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