Answer:
Let's call the price of a student ticket "s" and the price of an adult ticket "a".
From the first day's sales, we know that:
3s + 1a = 38
From the second day's sales, we know that:
3s + 2a = 52
We can use these two equations to solve for "s" and "a".
First, we'll use the first equation to solve for "a":
3s + a = 38
a = 38 - 3s
Next, we'll substitute this expression for "a" into the second equation:
3s + 2(38 - 3s) = 52
Simplifying and solving for "s", we get:
3s + 76 - 6s = 52
-3s = -24
s = 8
So the price of a student ticket is $8.
We can substitute this value back into the first equation to solve for "a":
3(8) + a = 38
24 + a = 38
a = 14
So the price of an adult ticket is $14.