Question

An air/gasoline vapor mix in an automobile cylinder has an initial temperature of 173 ∘C and a volume of 12.4 cm3 . If the mixture is heated to 567 ∘C with the pressure and amount held constant, what will be the final volume of the gas in cubic centimeters?

Answer 1

Step-by-step explanation:

We can solve this problem using the combined gas law:

(P1V1) / T1 = (P2V2) / T2

where P is the pressure, V is the volume, and T is the temperature, measured in kelvins (K). The amount of gas is assumed to be constant.

We need to convert the initial and final temperatures to kelvins by adding 273.15 to each temperature:

T1 = 173 + 273.15 = 446.15 K

T2 = 567 + 273.15 = 840.15 K

Substituting the given values into the equation and solving for V2, we get:

(1V1) / T1 = (1V2) / T2

V2 = (T2/T1) * V1

V2 = (840.15/446.15) * 12.4 cm3

V2 = 23.3 cm3 (rounded to one decimal place)

Therefore, the final volume of the gas will be 23.3 cubic centimeters.