Question

Graph the solution to the following inequality on the number line,(x + 6) (x-3) 20

Answer 1

If you have an equality of the form...

`(x+a)\cdot(x-b)\ge0`

The inequality can be writen as...

`a\leq x\leq b`

I'll show you how it looks like on the graph

the graph indicates that x is any value less than or equal to -6 or greater than or equal to 3, which is the red area

`\begin{gathered} x\leq-6 \\ x\ge3 \end{gathered}`