Question

7. How much ice is left over if 46 kJ of energy is added to 175 g of ice?

Answer 1

`m_(leftover)=37g`

Step-by-step explanation:

Hello!

In this case, since the melting process involves the heat added to the system, the heat of fusion and the mass of water:

`Q=m\Delta H_(fus)`

Thus, as it has been reported that the heat of fusion of ice is 333.6 J/g, we can compute the melted mass of ice as shown below:

`m=(Q)/(\Delta H_(fus)) =(46000J)/(333.6J/g)\\\\m=138g`

Thus, the ice leftover results:

`m_(leftover)=175g-138g\\\\m_(leftover)=37g`

Regards!