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Chris throws a ball upward. The height of the ball, in meters, t seconds after being

thrown is modeled by h (t)= 8t-5t² +4. After how many seconds will the ball reach
the ground?

User Kasi
by
8.8k points

1 Answer

5 votes

Answer:

When the ball hits the ground, its height will be 0 meters. Therefore, we need to solve the equation:

h(t) = 0

8t - 5t^2 + 4 = 0

We can solve this quadratic equation by factoring or by using the quadratic formula, but in this case, it's easier to use factoring:

(5t - 4)(t - 1) = 0

From this equation, we can see that either 5t - 4 = 0 or t - 1 = 0. Solving for t in each case, we get:

5t - 4 = 0 ==> t = 0.8 seconds

t - 1 = 0 ==> t = 1 second

Therefore, the ball will reach the ground after either 0.8 seconds or 1 second, depending on the initial height of the ball.

User Bogdan Sahlean
by
8.2k points
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