How is the series 3+5+7+...+51 represented in sigma notation?

asked Sep 10, 2024 211k views

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3 votes

The 3 ok so have a nice day

AterLux answered Sep 11, 2024

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3 votes

Answer:

The third one

Explanation:

The only one which gives the last number of the sequence is the third one as subbing in 16 you get 3×16 + 3 = 48 + 3 = 51

Mpettis answered Sep 14, 2024

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