Question

A 2kg object travels in the positive direction across a horizontal surface with a constant speed of 10ms . A force is exerted on the object for 4s , and the force increases linearly with respect to time. The table shows data about the magnitude of the applied force exerted on the object at different times. The force is exerted on the object in the opposite direction of the object’s displacement. What is the change in momentum of the object?

Answer 1

The change in momentum of the object is equal to the sum of the forces exerted on the object multiplied by the time for which the force was applied. The forces exerted on the object at different times are given in the table as F1, F2, F3, and F4.

The total change in momentum of the object is therefore equal to the sum of the forces multiplied by the time for which the force was applied: (F1 + F2 + F3 + F4) * 4s = 400 N*s. This is the change in momentum of the object during the period in which the force was applied

Step-by-step explanation: