Answer:
Below
Step-by-step explanation:
For Carbon:
40.002 % * 180.156 = 72.066 gm/mole C per mole of fructose
For Hydrogen:
6.714 % * 180.156 = 12.096 gm H
For Oxygen:
53.285% * 180.156 = 95.966 gm of O
Now use periodic table to find mole wts of each
72.066 / 12.011 = 6 moles of C per mole of fructose ( wt = 12.011)
12.096/ 1.008 = 12 moles of H (wt = 1.008)
95.966/15.999 = 6 moles of O (wt = 15.999)
C6 H12 O6 is MOLECULAR formula divide everything by 6
C H2 O is EMPIRICAL