Question

Chapter 10 Test

11. Nate uses a cube shaped bead with side lengths
measuring 6mm. Each bead has a circular hole in
the middle. The diameter of the circular hole is 3mm.
[not drawn to scale]

Answer 1

Explanation:

I'm guessing you need the volume of the bead with the hole.

We need to get the volume of two objects; a cube and a cylinder. We need the cylinder for the hole.

V(square) = 6^3

V(square) = 216 mm^3

V(cylinder) = pi(r^2)(h)

pi(1.5^2)(6)

Radius is half the diameter, and 6 represents the height, since it's as long as the cube.

V(cylinder) = 42.41 or 13.5pi

We need to do V(s) - V(c) to find the volume of the bead.

216 - 13.5pi = 173.588 or 173.59 or 173.6

I hope this helps!