Answer: 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.
Step-by-step explanation:
balanced chemical equation for the reaction between aluminum and oxygen is:
4Al + 3O2 → 2Al2O3
moles of O2 = mass / molar mass = 24 g / 32 g/mol = 0.75 mol
moles of Al2O3 = (2/3) * moles of O2 = (2/3) * 0.75 mol = 0.5 mol
Therefore, 0.5 moles of aluminum oxide can be produced from 24 grams of oxygen gas.