Answer:
To find the equation of a line that goes through a given point and is perpendicular to a given line, we can use the following steps:
Rewrite the given line in slope-intercept form y = mx + b, where m is the slope and b is the y-intercept.
Determine the slope of the line that is perpendicular to the given line. The slope of a line perpendicular to a line with slope m is -1/m.
Use the point-slope form of the equation of a line to write the equation of the line that goes through the given point with the slope found in step 2.
Given the point (8, 1) and the line 2y + 4x = 12, we can rewrite the line in slope-intercept form by solving for y:
2y + 4x = 12
2y = -4x + 12
y = -2x + 6
The slope of the given line is -2.
The slope of the line perpendicular to the given line is -1/-2 = 1/2.
Using the point-slope form of the equation of a line, we can write the equation of the line that goes through the point (8, 1) with slope 1/2:
y - 1 = (1/2)(x - 8)
Simplifying this equation, we get:
y - 1 = (1/2)x - 4
y = (1/2)x - 3
Therefore, the equation of the line that goes through the point (8, 1) and is perpendicular to the line 2y + 4x = 12 is y = (1/2)x - 3.
Explanation: