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Write an equation
perpendicular to y =
2/5x+ 4 with a
y-intercept of -3

User Caot
by
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1 Answer

6 votes

Answer:

y = (-5/2)x - 3

Explanation:

To find an equation of a line that is perpendicular to the given line and passes through the point (0, -3), we need to use the fact that perpendicular lines have opposite reciprocal slopes.

The given line has a slope of 2/5, so the slope of the line perpendicular to it is:

-1 / (2/5) = -5/2

This means that the equation of the perpendicular line has the form:

y = (-5/2)x + b

where b is the y-intercept we want to find.

Since the line passes through the point (0, -3), we can substitute these values into the equation and solve for b:

-3 = (-5/2)(0) + b

b = -3

Therefore, the equation of the line perpendicular to y = 2/5x + 4 with a y-intercept of -3 is:

y = (-5/2)x - 3