Question

If I have 0.4 moles of a gas at a temperature of 17 C and a volume of 7.0 L, what is the

pressure of the gas?

Answer 1

4.20 atm

Step-by-step explanation:

PV = nRT

convert the temperature from Celsius to Kelvin:

T(K) = T(C) + 273.15

T(K) = 17 + 273.15

T(K) = 290.15 K

plug in the values:

n = 0.4 moles

V = 7.0 L

R = 0.08206 L atm / (mol K) (Gas constant)

T = 290.15 K

PV = nRT

P = nRT / V

P = (0.4 moles) x (0.08206 L atm / (mol K)) x (290.15 K) / (7.0 L)

P = 4.20 atm (rounded to two significant figures)

Therefore, the pressure of the gas is 4.20 atm.