Question

1.5 moles of gas are contained in a 5.8 L chamber with a temperature of 294 K. What is the

pressure inside the chamber?

Answer 1

Answer: 6.04 atm

Step-by-step explanation:

PV = nRT

plug in the given values and solve for P:

n = 1.5 moles

V = 5.8 L

R = 0.08206 L·atm/(mol·K) (gas constant)

T = 294 K

P = nRT/V

P = (1.5 mol) x (0.08206 L·atm/(mol·K)) x (294 K) / (5.8 L)

P = 6.04 atm

Therefore, the pressure inside the chamber is 6.04 atm