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Two parallel lines are cut by a transversal as shown below. Suppose m∠1=63°. Find m∠6 and m∠7.

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Answer: Since lines l and m are parallel, we can use the fact that corresponding angles are congruent. Therefore:

m∠1 = m∠6 (corresponding angles)

m∠6 + m∠2 = 180° (supplementary angles, as angles 6 and 2 form a straight line)

m∠2 = m∠7 (corresponding angles)

m∠3 = m∠7 (alternate interior angles)

m∠1 + m∠4 = 180° (supplementary angles, as angles 1 and 4 form a straight line)

m∠3 + m∠4 = 180° (supplementary angles, as angles 3 and 4 form a straight line)

We know that m∠1 = 63°, so we can use the equations above to find m∠6 and m∠7:

m∠1 = m∠6, so m∠6 = 63°.

m∠6 + m∠2 = 180°, so m∠2 = 180° - m∠6 = 180° - 63° = 117°.

m∠2 = m∠7, so m∠7 = 117°.

m∠3 = m∠7, so m∠3 = 117°.

m∠1 + m∠4 = 180°, so m∠4 = 180° - m∠1 = 180° - 63° = 117°.

m∠3 + m∠4 = 180°, so m∠3 + 117° = 180°, which means m∠3 = 63°.

Therefore, the measures of the angles are:

m∠1 = 63°

m∠2 = 117°

m∠3 = 63°

m∠4 = 117°

m∠6 = 63°

m∠7 = 117°

Explanation:

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