123k views
3 votes
Kell high school sells child and adult football tickets. last Friday they sold 412 tickets for 2,725,50 if a child ticket costs 3 and an adult ticket costs 7.50 how many of each type of ticket did they sell

User Safrazik
by
8.1k points

1 Answer

5 votes

Answer:

Explanation:

Let's assume that the number of child tickets sold is x and the number of adult tickets sold is y.

From the problem statement, we know that:

The total number of tickets sold is 412, so x + y = 412.

The total amount of money collected from selling these tickets is 2,725.50, so 3x + 7.50y = 2,725.50.

We can use these two equations to solve for x and y. One way to do this is to use substitution:

Solve the first equation for x: x = 412 - y.

Substitute this expression for x into the second equation: 3(412 - y) + 7.50y = 2,725.50.

Simplify and solve for y: 1,236 - 3y + 7.50y = 2,725.50, so 4.50y = 1,489.50, and y = 330.

Use the first equation to find x: x = 412 - y, so x = 82.

Therefore, Kell High School sold 82 child tickets and 330 adult tickets.

User Alex Myers
by
8.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.