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Kell high school sells child and adult football tickets. last Friday they sold 412 tickets for 2,725,50 if a child ticket costs 3 and an adult ticket costs 7.50 how many of each type of ticket did they sell

User Safrazik
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1 Answer

5 votes

Answer:

Explanation:

Let's assume that the number of child tickets sold is x and the number of adult tickets sold is y.

From the problem statement, we know that:

The total number of tickets sold is 412, so x + y = 412.

The total amount of money collected from selling these tickets is 2,725.50, so 3x + 7.50y = 2,725.50.

We can use these two equations to solve for x and y. One way to do this is to use substitution:

Solve the first equation for x: x = 412 - y.

Substitute this expression for x into the second equation: 3(412 - y) + 7.50y = 2,725.50.

Simplify and solve for y: 1,236 - 3y + 7.50y = 2,725.50, so 4.50y = 1,489.50, and y = 330.

Use the first equation to find x: x = 412 - y, so x = 82.

Therefore, Kell High School sold 82 child tickets and 330 adult tickets.

User Alex Myers
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