Question

If a wave of wavelength 1m and another wave of wavelength 3m are both transmitted at a velocity of 120m/s, what is the frequency difference between these signals?

Answer 1

The velocity of a wave is given by the product of its wavelength and frequency:

velocity = wavelength x frequency

Rearranging this equation, we can solve for frequency:

frequency = velocity / wavelength

For the wave with a wavelength of 1 m:

frequency1 = 120 m/s / 1 m = 120 Hz

For the wave with a wavelength of 3 m:

frequency2 = 120 m/s / 3 m = 40 Hz

The frequency difference between these two signals is the absolute value of the difference between their frequencies:

|frequency1 - frequency2| = |120 Hz - 40 Hz| = 80 Hz

Therefore, the frequency difference between these signals is 80 Hz.