Question

Dotermine how much elastic potential energy a spring has stored in it it the

spring constant is 50 M/m and the spring is stretched a distance of 2 m

Answer 1

The elastic potential energy (U) stored in a spring is given by the formula:

U = (1/2)kx²

where k is the spring constant and x is the displacement from the equilibrium position.

In this case, k = 50 M/m (assuming M/m represents the unit of the spring constant) and x = 2 m. Substituting these values into the formula, we get:

U = (1/2)(50 M/m)(2 m)²

= (1/2)(50 M/m)(4 m²)

= 100 M

Therefore, the spring has 100 M (units of energy) of elastic potential energy stored in it when it is stretched a distance of 2 m.

Step-by-step explanation: