Question

Find the equation of a line, in Slope Intercept Form, that has a slope of 3 and passes through the point (-4, 2).

Answer 1

Answer: y = 3x + 14

Explanation:

The slope-intercept form is y=mx+b

We will plug in -4 for the x, 2 for the y, and 3 for the m, and leave b alone to solve for it.

2 = 3(-4) + b

2 = -12 + b

b = 14

The final equation is y = 3x + 14.

Hope this helps!

Answer 2

`(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ 3 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ 3}(x-\stackrel{x_1}{(-4)}) \implies y -2= 3 (x +4) \\\\\\ y-2=3x+12\implies {\Large \begin{array}{llll} y=3x+14 \end{array}}`