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The length of a rectangle is twice its width. Find its area if its perimeter is 7 1/3 cm.

please help ive been stuck on this for a day tyy !!

User Elias Naur
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1 Answer

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Answer:

Let's start by using the information given in the problem to write an equation for the perimeter of the rectangle:

Perimeter = 2(length + width)

We know that the length of the rectangle is twice its width, so we can write:

length = 2*width

Substituting this expression into the equation for the perimeter, we get:

Perimeter = 2(2*width + width)

Simplifying this expression, we get:

Perimeter = 6*width

We are given that the perimeter is 7 1/3 cm, which we can convert to a mixed number:

Perimeter = 7 + 1/3 = 22/3

Substituting this value into the equation above, we get:

22/3 = 6*width

Solving for the width, we get:

width = 22/3 ÷ 6 = 11/9

Now that we have the width, we can use the expression for the length to find its value:

length = 2*width = 2(11/9) = 22/9

Finally, we can use the formula for the area of a rectangle, A = length * width, to find the area:

A = (22/9) * (11/9) = 242/81 square cm

Therefore, the area of the rectangle is 242/81 square cm.

User Richards
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