Question

Write the standard form of the equation of the line passing through the point (1, 5) and perpendicular to the line 4x - 7y = – 28.

Answer 1

`\begin{gathered} \text{The equation of line is,} \\ 4x-7y=-28 \\ 7y=4x+28 \\ y=(4)/(7)x+4 \\ \text{The slope is }\Rightarrow m=(4)/(7) \\ \text{The perpendicular slope}\Rightarrow m^(\prime)=-(7)/(4) \\ The\text{ equation passing through (1,5)} \\ y-y_1=m^(\prime)(x-x_1) \\ y-5=-(7)/(4)(x-1) \\ 4y-20=-7x+7 \\ 4y=-7x+27 \\ y=-(7)/(4)x+(27)/(4)(\text{Ans)} \end{gathered}`