Question

Adding and Subtracting Algebraic Fractions Question.

I cant figure out how the answer: 2d + 3 over d² is found. Can someone explain it by solving the question in steps please. I think I have missed a step.

Answer 1

to sum fraction of different denominator, we have to have the same denominator so we multiply d on top and bottom i.e 2d/d^2 +3/d^2 = (2d+3)/d^2

Explanation:

multiply top and bottom does not change the equation.

Answer 2

`(2d + 3)/(d^2)`

Explanation:

`(2)/(d) + (3)/(d^2) =`

The denominators are d and d². To add fractions, you need a common denominator. The least common denominator (LCD) of d and d² is d². The second fraction already has the LCD as a denominator. We need a denominator of d² in the first fraction. We multiply the first fraction by d/d.

`= (d)/(d) * (2)/(d) + (3)/(d^2)`

`= (2d)/(d^2) + (3)/(d^2)`

`= (2d + 3)/(d^2)`