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Shape ABCD was enlarged using a scale factor of -4 and centre (1,2) to give shape A B C D what were the coordinates of A and B

Shape ABCD was enlarged using a scale factor of -4 and centre (1,2) to give shape-example-1

2 Answers

7 votes

Answer:

It is not possible to have a scale factor of -4 as a scale factor is always a positive number. However, assuming that the scale factor is 4 and that shape ABCD is being enlarged with center (1,2), we can use the following formula to find the coordinates of the image shape A'B'C'D':

(x', y') = (h + 4(x - h), k + 4(y - k))

where (h, k) is the center of enlargement and (x, y) are the coordinates of the original point.

Using this formula, we can find the coordinates of A' and B' as follows:

For point A:

The original coordinates of A are (1, 1)

Plugging in the values, we get:

(x', y') = (1 + 4(1 - 1), 2 + 4(1 - 2)) = (1, -2)

Therefore, the coordinates of A' are (1, -2)

For point B:

The original coordinates of B are (3, 1)

Plugging in the values, we get:

(x', y') = (1 + 4(3 - 1), 2 + 4(1 - 2)) = (9, -2)

Therefore, the coordinates of B' are (9, -2)

User TealShift
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2 votes

The original coordinates for A and B are (5,4) and (3,3), respectively. The lines from B' to (10,5) and from A' to (4,5) intersect at the center of enlargement, (1,2).

The coordinates of the original shape's vertices, A and B, were not provided, so let's use the given information to deduce them. The enlargement with a scale factor of -4 and a center at (1,2) indicates a reflection and enlargement. To find the original coordinates, we can use the formula for enlarging a point (x, y) about a center (h, k) with a scale factor of r:


\[ x' = h + r \cdot (x - h) \]


\[ y' = k + r \cdot (y - k) \]

Using A'(-7,-6) as an example:


\[ -7 = 1 - 4 \cdot (x - 1) \]


\[ -6 = 2 - 4 \cdot (y - 2) \]

Solving these equations yields the original coordinates for A as (5,4). Similarly, for B', using the same formula:


\[ -11 = 1 - 4 \cdot (x - 1) \]


\[ -2 = 2 - 4 \cdot (y - 2) \]

Solving these equations yields the original coordinates for B as (3,3).

Now, the line from B'(-11,-2) to (10,5) intersects with the line from A'(-7,-6) to (4,5) at the point (1,2), which is consistent with the center of enlargement.

User Gardelin
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7.8k points