Question

A student measures a piece of rope and found that it was 1. 26m long. If the actual length of the rope is 1. 25m what is the percentage error int the measurement​

Answer 1

0.80%

Explanation:

Actual length of the rope: 1.25m

Measured length of the rope: 1.26m

Error: (1.26 - 1.25)m - 0.01m

=
`(0.01)/(1.25)` * 100%

= 0.80% or 0.8%