Question

2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O

In the above equation, how many grams of N2 can be made when 127 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

Answer 1

Calculate the number of moles of CuO:

127 g CuO x (1 mol CuO/63.5 g CuO) = 2.00 mol CuO

Use the balanced equation to determine the number of moles of N2 produced from 2.00 mol of CuO:

2 NH3 + 3 CuO -> 3 Cu + N2 + 3 H2O

3 mol N2/2 mol CuO = 1.50 mol N2

Calculate the mass of N2 produced using the molar mass of nitrogen:

1.50 mol N2 x 28 g N2/mol = 42 g N2

Therefore, 127 grams of CuO will produce approximately 42.0 grams of N2.

Answer 2

Answer:First, we need to determine the number of moles of CuO in 127 grams:

127 g CuO x (1 mol CuO/63.5 g CuO) = 2.0 mol CuO

Using the balanced equation, we can determine the number of moles of N2 produced:

2 NH3 + 3 CuO -> 3 Cu + N2 + 3 H2O

From the equation, we see that 3 moles of CuO produce 1 mole of N2. So, 2 moles of CuO produce:

1/3 mol N2 = 0.333 mol N2

Now, we can use the molar mass of nitrogen to convert the number of moles of N2 to grams:

0.333 mol N2 x 14 g/mol = 4.7 g N2

Rounding to the nearest tenth, we get:

4.7 g N2 (rounded to the nearest tenth)

Step-by-step explanation: