Question

Females who do not show the trait for hemophilia may be homozygous dominant (XNXN) or heterozygous (XNXn). A

a heterozygous female is called a carrier. Examination of offspring can often determine which genotype the parents have. If any child (son or daughter) has hemophilia, then the female must be heterozygous. If her son has hemophilia, he has genotype XnY. He inherited the Y from the father, so the other allele is his genotype (Xn) had to come from the mother. If a daughter has hemophilia (XnXn), she inherited an Xn from each parent, thus making the genotype for the normal mother XNXn.
What would be the genotype for the female who marries into the family in generation III? Type Answer Here

Answer 1

Answer:Without additional information, it is not possible to determine the genotype of the female who marries into the family in generation III. The only information given is that she marries into the family, but we do not know her genetic history or whether she has any family members with hemophilia.

If we assume that the female who marries into the family is not a carrier or affected by hemophilia herself, then she would have the genotype XNXN (homozygous dominant) for the factor VIII gene on her X chromosome. This is because females have two X chromosomes, one inherited from each parent, and can be either homozygous dominant (XNXN), heterozygous (XNXn), or homozygous recessive (XnXn) for the factor VIII gene. However, it is important to note that this assumption may not be accurate without additional information.

Step-by-step explanation: