37.1k views
3 votes
The minimum of the graph of a quadratic function is located at (–1, 2). The point (2, 20) is also on the parabola. Which function represents the situation?

f(x) = (x + 1)2 + 2
f(x) = (x – 1)2 + 2
f(x) = 2(x + 1)2 + 2
f(x) = 2(x – 1)2 + 2

User Terenoth
by
8.4k points

1 Answer

7 votes

Answer:

f(x) = 2(x + 1)^2 + 2

Explanation:

This question can be answered in two ways: Mathematically and Graphing.

Both are shown on the attached graph.

Mathematically:

One can solve the equations with the given values of x (-1 and 2) to see which one results in y values of (2 and 20):

Equation See the results in the attachment

f(x) = (x + 1)^2 + 2 Includes: (-1,2)

f(x) = (x – 1)^2 + 2

f(x) = 2(x + 1)^2 + 2 (-1,2) and (2,20)

f(x) = 2(x – 1)^2 + 2

Graphing

See the attached graph. Only one of the equations intersect the two given points (-1,2) and (2,20). y = 2(x+1)^2 + 2

The minimum of the graph of a quadratic function is located at (–1, 2). The point-example-1
User ArneHugo
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories