Question

PLSSSS HELPP

h=-5t^2+20t what is the maximum hight of the ball and how can you tell by looking at the equation

h=hight
t=time

Answer 1

t= 2 at max h = 20

(2,20)

Explanation:

-5t^2+20t

=-5(t^2 -4t+4) +20

= -5(t-2)^2 +20

vertex = (2,20)

or

h=-5t^2+20t

h'= -10t+20=0

t= 20/10=2 sec to max height

double it to hit the ground = 4 seconds in the air

max h= h(2)= -5(2)^2 +20(2)= 20 meters high