Answer:
(x^2+3) ( 2x+5)
Explanation:
2x^3 + 5x^2 + 6x+15
We can use factoring by grouping.
Factor an x^2 from the first two terms and a 3 from the last two terms.
2x^3 + 5x^2 + 6x+15
x^2 ( 2x+5) + 3( 2x+5)
Now factor out (2x+5).
(2x+5) ( x^2 +3)
The factored form is
(x^2+3) ( 2x+5)