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How many solutions does this linear system have?

Y=2/3x+2,
6x-4y=-10


A-one solution -0.6,-1.6
B- one solution -0.6,1.6
C-no solution
D-infinite number of solutions

User Flower
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1 Answer

6 votes

Answer:

there is only one solution, the answer is (A) one solution -0.6,-1.6.

Explanation:

To find out how many solutions the system has, we can solve it using either substitution or elimination method. Let's use the elimination method here:

Y = (2/3)x + 2 --- equation 1

6x - 4y = -10 --- equation 2

To eliminate y, let's multiply equation 1 by 4:

4y = 8/3x + 8

Now, we can substitute this expression for 4y into equation 2 and simplify:

6x - (8/3x + 8) = -10

Multiplying both sides by 3 to get rid of the fraction:

18x - 8x - 24 = -30

Simplifying further:

10x = -6

x = -0.6

Now we can substitute x = -0.6 into either equation 1 or equation 2 to find y:

Using equation 1:

y = (2/3)(-0.6) + 2 = 1.6

Therefore, the solution to the system is (-0.6, 1.6).

Since there is only one solution, the answer is (A) one solution -0.6,-1.6.

User Satumba
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7.1k points