Question

A rectangular box has a length of 7 feet and a height of 11 feet. The length of the

diagonal of the box is 20 feet. What is the width of the box?
three-dimensional

Answer 1

Using the Pythagorean theorem, we have:

(diagonal)^2 = (length)^2 + (height)^2 + (width)^2

Simplifying this equation and plugging in the given values, we get:

20^2 = 7^2 + 11^2 + w^2

400 = 49 + 121 + w^2

400 = 170 + w^2

230 = w^2

w = sqrt(230)

w ≈ 15.165 feet

Therefore, the width of the box is approximately 15.165 feet.