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Find the area of the shaded segment

Find the area of the shaded segment-example-1
User Lionels
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4 votes

Answer:

9.83 mm^2

Explanation:

Radius = diameter/2 = 8/2 = 4

Area of circle: A=πr^2 = π4^2 = 16π

1/2 area of circle = 16π/2 = 8π

Since the angle = 60o, the area is 1/3 of half circle (the half circle has angle of 180o) => Area of 60o = 8π/3 = 8/3π

The last step is to find the area of the triangle.

Since the 2 sides are radius => it is isosceles triangle

the obtuse angle of the triangle = 180 - 60 = 120o

therefore the other 2 angles are 60/2 = 30o

If you draw a line from the center of the circle perpendicular to the side of the triangle (see attachment) => we have 2 equal right triangles △ACO = △BCO

so for the right triangle, radius will be the hypotenuse, the angle is 30, we need to solve for OC

sin(30o) = opposite/hypotenuse

1/2 = OC/4

OC = 2

Pythagorean theorem: c^2 = a^2 + b^2

4^2 = 2^2 + b^2

b^2 = 16 - 4 = 12

b = √12 = 3.46 or BC = AC = 3.46

=> AB = 3.46 x 2 = 6.92

A=1/2hb

Area of triangle ABO = 1/2(OC)(AB) = 1/2(2)(6.92) = 6.92

Area of the shaded segment = area of circle - (1/2 area of circle + area of 60o + area of triangle)

=> π4^2 - (8π + 8/3π + 6.92)

=> 16π - 8π - 8/3π - 6.92

=> 16/3π - 6.92

=> 16/3(3.14) - 6.92 = 9.83

Find the area of the shaded segment-example-1
User Ankit Goel
by
7.2k points

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