Answer: Your welcome!
Step-by-step explanation:
The volume of bromine gas (Br2) produced can be calculated as follows:
75.5 L of chlorine gas (Cl2) reacts with 155 g of HBr to produce Br2 and HCl.
Moles of Cl2 = 75.5 L × (1 mol/22.4 L) = 3.36 mol
Moles of HBr = 155 g/80.91 g/mol = 1.92 mol
The mole ratio of Cl2 to HBr is 3.36:1.92 = 1.75:1
The theoretical yield of Br2 is therefore 1.92 mol.
At STP, 1 mol of Br2 occupies a volume of 22.4 L.
Volume of Br2 produced = 22.4 L/mol × 1.92 mol = 43.2 L