Given:-
- A triangle whose perimeter is 10m² + 11m + 8.
- Two sides are 10m² - 6 and 10m - 1.
To find:-
- The expression for the third side.
Answer:-
As we know that the perimeter is sum of side lengths of all the triangle. So let the measure of the third side be " x " . So we have ,
P = 10m² - 6 + 10m - 1 + x
10m² - 11m + 8 = 10m² + 10m - 7 + x
10m² - 11m + 8 - 10m² - 10m + 7 = x
-11m - 10m + 8 + 7 = x
-21m + 15 = x
Hence the side measure of the third side is -21m + 15.
and we are done!