Answer:
Step-by-step explanation:
The balanced chemical equation for the reaction between NaOH and HCl is:
NaOH + HCl → NaCl + H2O
According to the balanced equation, one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of H2O. Therefore, we need to calculate the number of moles of NaOH and HCl required to produce 2 grams of NaCl.
The molar mass of NaCl is 58.44 g/mol. Therefore, 2 grams of NaCl is equal to 2/58.44 = 0.0341 moles of NaCl.
Since NaOH and HCl react in a 1:1 molar ratio, we need 0.0341 moles of HCl to react with 0.0341 moles of NaOH.
To calculate the volume of 1.5 M HCl required to provide 0.0341 moles of HCl, we can use the following formula:
moles = concentration × volume
Rearranging the formula, we get:
volume = moles / concentration
Substituting the values, we get:
volume of 1.5 M HCl = 0.0341 / 1.5 = 0.0227 L
Therefore, 0.0227 L of 1.5 M HCl is required to react with 0.5 M NaOH to produce 2 grams of NaCl.
Note: It is important to handle the strong acids and bases with care as they can be hazardous. Safety equipment, such as gloves and goggles, should be used while performing the experiment.