Answer:
Step-by-step explanation: First, look at the intercepts for lines A and B.
Line A has an intercept of 4
Line B has an intercept of 12
Then choose two points on line a that perfectly go through without being a decimal on line A. I'll choose 0,4 and 1,6. The subtract to find the slope of the line, you will format this as y/x.
(x1-x2) 0-1=-1 so -1 is your denominator.
(y1-y2) 4-6=-2 so -2 is your numerator
That leaves us with the slope of -2/-1 or simply, just 2.
You know that slope intercept for is y=mx+b so the equation would be:
y=2x+4 for line A.
Now do the same thing for line B.
(0,12), (3,10)
0-3= -3 so y/-3
12-10 is 2 so 2/-3 or just -2/3
You put that into slope intercept form and that would be:
y=-2/3x+12 for line B
To Find the point of intersect just find where they're intersecting so (3,10) is the solution to the system of equations.