Answer: 945 Joules of heat energy are needed to heat 50 grams of iron from -10°C to 32°C.
Explanation:The specific heat capacity of iron is 0.45 J/g°C.
To calculate the heat needed, we need to use the formula:
Q = m * c * ΔT
where Q is the amount of heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
Substituting the given values:
Q = 50 g * 0.45 J/g°C * (32°C - (-10°C))
Q = 50 g * 0.45 J/g°C * 42°C
Q = 945 J
Therefore, 945 Joules of heat energy are needed to heat 50 grams of iron from -10°C to 32°C.