Question

URGENT!!! someone explain this to me

What is the correct form to solve for x:
12-3 = 60
O log60 12 = x - 3
O log₁2 (57) = x
O log₁2 (63) = x
O log12 (60) + 3 = x

Answer 1

`log_(12) \text{ } 60 + 3=x`

Explanation:

For some exponential equation
`a^(x) =y` the logarithmic form becomes
`x=log_a \text{ } y`

The base of the exponent or power becomes the base of the logarithm

so,

`12^((x-3)) =60` becomes,
`x - 3=log_(12) \text{ } 60` or
`log_(12) \text{ } 60 = x -3`

We simplify by getting x on the one side, to get:

`log_(12) \text{ } 60 + 3=x`