ANSWERS
Question 1: By multiplying the first or top equation by 2
Question 2:
![2(3x+2y=12)\\\\=[2(3x)+2(2y)=2(12)]\\\\=6x+4y=24](https://img.qammunity.org/2024/formulas/mathematics/high-school/2r1avq80bueaenvae2vgyf8n9f31bbi6xn.png)
Question 3:
Subtract each like term;
[6x + 4y = 24]
- [6x + 3y = 21]
__________
[ 0 + y = 3 ] so, y = 3
Question 4:
Use the equation, 3x + 2y = 12 and substitute y =3:

Question 5:
An ordered pair is (x, y) so (2, 3)
Question 6:
So we check our answer but substituting x = 2 and y = 3, in 6x + 3y =21,
