Question

[(40+5)-3^2] divided by 9*2 how to work it out see steps please

Answer 1

`\stackrel{ {\Large \begin{array}{llll} \mathbb{PEMDAS} \end{array}} }{[(4+5)-3^2] / 9\cdot 2\implies [(4+5)-9] / 9\cdot 2} \\\\\\\ [(9)-9] / 9\cdot 2 \implies [0] / 9\cdot 2\implies \text{\LARGE 0}`

now, we could have done the 9*2 multiplication, however moving from Left to Right we do the division first, and it doesn't really matter what the divisor is, 0 ÷ anything = 0.