Answer:
To determine the least amount of traffic flow that can be allowed on the block of Winooski Avenue East between Willow and Jay without disrupting the hourly flow into and out of the network, we can use Kirchhoff's Laws, which state that the total flow of traffic into a node equals the total flow of traffic out of the node, and the sum of the flows around a loop is zero.
Step-by-step explanation:
Let's define the flow of traffic on the block of Winooski Avenue East between Willow and Jay as x, and set up a system of equations based on Kirchhoff's Laws:
For the node at Willow:
65 + x = 70 + 55
For the node at East Winooski:
80 = 30 + x + 40
For the node at West Winooski:
50 = 5 + 75 - x
For the node at Shelburne:
x = 65 + 40 - 50
Simplifying each equation, we have:
x = 10 (from the Willow equation)
x = 10 (from the East Winooski equation)
x = 20 (from the West Winooski equation)
x = 55 (from the Shelburne equation)
The minimum value of x that satisfies all of these equations is 20. Therefore, the least amount of traffic flow that can be allowed on the block of Winooski Avenue East between Willow and Jay without disrupting the hourly flow into and out of the network is 20.