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What are the height and the diameter of the cylinder, to the nearest hundredth of a foot?

What are the height and the diameter of the cylinder, to the nearest hundredth of-example-1
User Aaron G
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1 Answer

17 votes
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Given:

a.) The surface area of a cylinder is about 158.83 sq. ft.

b.) The height of the cylinder is 3 times the radius.

Let's determine the height and radius of the cylinder.

Recall the formula in getting the surface area of a cylinder:


\text{ Surface Area = 2}\pi rh\text{ + 2}\pi\text{r}^2

But,

h = 3r (h = height, r = radius)

Let's first find the radius:


\text{ Surface Area = 2}\pi rh\text{ + 2}\pi\text{r}^2
\text{ 155.83 = 2}\pi\text{\lparen r\rparen\lparen3r\rparen+ 2}\pi\text{r}^2
\text{ 155.83 = 6}\pi r^2\text{ + 2}\pi r^2
\text{ 8}\pi r^2\text{ = 155.83}
\text{ }\frac{8\pi\text{r}^2}{8\pi}\text{ = }(155.83)/(8\pi)
\text{ r}^2\text{ = 6.20}
\text{ }√(r^2)\text{ = }√(6.20)
\text{ r }\approx\text{ 2.49 feet}

Therefore, the radius of the cylinder is approximately 2.49 feet.

For the height:

h = 3r = 3(2.51) = 7.47 feet

In Summary:

The radius is 2.49 feet

The height is 7.47 feet

User Kevin Jin
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