Question

I don’t understand i need help and it’s time sensitive i have 3 mins

Answer 1

From the given image,

`\cos(\theta)=(9)/(41)`

Recall the trigonometric identity:

`\sin^2((\theta)/(2))=(1-\cos(\theta))/(2)`

Substitute cos (θ) = 9/41 into the equation:

`\sin^2((\theta)/(2))=(1-(9)/(41))/(2)=(41-9)/(82)=(32)/(82)=(16)/(41)`

Therefore,

`\sin((\theta)/(2))=\sqrt{(16)/(41)}=(4√(41))/(41)`

Therefore, the required answer is:

sin(θ/2) = (4√41)/41

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