Question

Find the distance between the two points rounding to the nearest tenth (if necessary).

(2,−4) and (7,8)

Answer 1

Given two points (2,-4) and (7,8)

To find - The distance between given points.

We know the formula that is used to find the distance is given as

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

We let P = (2,-4)

and Q = (7,8)

`x_1=2, y_1=-4\\x_2=7,y_2=8`

on substituting we get

`d=√((7-2)^2+(8+4)^2)\\ d=√((5)^2+(12)^2) \\d=√(25+144) \\d=√(169)\\ d=13`

Hence we get the distance between (2,-4) and (7,8) is 13.

Final answer - The distance is 13.

Answer 2

d = 13

Explanation:

First, the distance formula is needed:

`d = \sqrt{(x_(2) - x_(1) )^(2) +(y_(2) - y_(1 ))^(2) }`

Next we assign the points

(2,-4) is point 1, (7,8) is point 2

`d = \sqrt{(7 - 2 )^(2) +(8 - (-4))^(2) } \\d = \sqrt{5^(2) +12^(2) } \\d = √(25 + 144)\\ d = √(169) \\d = 13`